C語(yǔ)言版簡(jiǎn)易計(jì)算器，包含幾個(gè)小功能，而且比較精簡(jiǎn)，適合新手了解整合框架結(jié)構(gòu)
源代碼如下：
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
//預(yù)處理指令
int main(void)
{
double bNumber, Number, Result; //給加減乘除定義的變量
int No; //選項(xiàng)的定義變量
double a, b, c, x1, x2, Rad; //給一元一次方程定義的變量
int Ary_10; //定義進(jìn)制的變量
char string[32]; //二進(jìn)制變量定義
system ("title: www.sztianhecheng.cn");
while(1)
{
//界面
printf ("┏ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┓\n");
printf ("┇請(qǐng)選擇你要計(jì)算的方法: ┇\n");
printf ("┣ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┫\n");
printf ("┇ 加法請(qǐng)按_1 進(jìn)制轉(zhuǎn)換_5 ┇\n");
printf ("┇ 減法請(qǐng)按_2 求一元二次方程_6 ┇\n");
printf ("┇ 乘法請(qǐng)按_3 ┇\n");
printf ("┇ 除法請(qǐng)按_4 退出_0 ┇\n");
printf ("┗ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┛\n");
printf ("Please write down the number:");
scanf ("%d",&No);
if (No == 1)
{
// 加法
printf (" 請(qǐng)輸入被加數(shù):");
scanf ("%lf",&bNumber);
printf (" 請(qǐng)輸入加數(shù):");
scanf ("%lf",&Number);
Result = bNumber + Number;
printf (" 結(jié)果是: %lf\n\n",Result);
}
else if (No == 2)
{
// 減法
printf (" 請(qǐng)輸入被減數(shù):");
scanf ("%lf",&bNumber);
printf (" 請(qǐng)輸入減數(shù):");
scanf ("%lf",&Number);
Result = bNumber - Number;
printf (" 結(jié)果是: %lf\n\n",Result);
}
else if (No == 3)
{
// 乘法
printf (" 請(qǐng)輸入被乘數(shù):");
scanf ("%lf",&bNumber);
printf (" 請(qǐng)輸入乘數(shù):");
scanf ("%lf",&Number);
Result = bNumber * Number;
printf (" 結(jié)果是: %lf\n\n",Result);
}
else if (No == 4)
{
// 除法
printf (" 請(qǐng)輸入被除數(shù):");
scanf ("%lf",&bNumber);
printf (" 請(qǐng)輸入除數(shù):");
scanf ("%lf",&Number);
Result = bNumber / Number;
printf (" 結(jié)果是: %lf\n\n",Result);
}
else if (No == 5)
{
//進(jìn)制轉(zhuǎn)換的代碼
printf("請(qǐng)輸入需要轉(zhuǎn)換的十進(jìn)制數(shù):");
scanf("%d", &Ary_10);
itoa (Ary_10, string ,2);
printf("二進(jìn)制: %s\n", &string);
printf("八進(jìn)制: %o\n", &Ary_10);
printf("十六進(jìn)制: %x\n", &Ary_10);
}
else if (No == 6)
{
//求一元二次方程的解的代碼
printf("請(qǐng)輸入一元一次方程的a,b,c三個(gè)數(shù):");
scanf("%lf%lf%lf",&a,&b,&c);
Rad = b*b - 4*a*c;
if (Rad > 0)
{
x1 = -b + sqrt(Rad) / (2*a);
x2 = -b - sqrt(Rad) / (2*a);
printf("有兩個(gè)解 x1 = %lf, x2 = %lf\n", &x1, &x2);
}
else if (Rad == 0)
{
x1 = -b / (2*a);
printf("只有一個(gè)解 x1 = %lf\n", &x1);
}
else
{
printf("無解\n");
}
}
else if (No == 0)
{
// 退出程序
break;
}
else
{
// 輸入的選項(xiàng)不對(duì)
printf(" 請(qǐng)輸入正確的數(shù)字。\n\n");
}
system ("pause"); //按任意鍵繼續(xù)
system ("cls"); //清屏
}
return 0;
getchar();
}
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